### Robert is always curious in creating formulas, for solving mathematical problems, of his own by repeated trial and error method. One day he found a formula for finding the surface area of the hexagonal pyramid. What should be the correct formula for the surface area of the hexagonal pyramid?

$3(bh + ab)$
 $=$ b h $\times$ $6$ $+$ b a
2. Area of bigger triangle $= \left( \dfrac{ 1 }{ 2 } \times b \times h \right)$
Also, the area of the hexagon can be divided into $6$ small triangles.
So, the area of a smaller triangle in the hexagon $= \left( \dfrac{ 1 }{ 2 } \times b \times a \right)$
3. So, the combined surface area of the figure can be calculated as: \begin{align} & 6 \left( \dfrac{ 1 }{ 2 } \times b \times h \right) + 6 \left( \dfrac{ 1 }{ 2 } \times b \times a \right) \\ = & 3bh + 3ab \\ = & 3(bh + ab) \end{align}