### Joseph throws a dice. What is the probability that he will get an odd number?

**Answer:**

1 |

2 |

**Step by Step Explanation:**

- Let us assume
*S*,*E*, and*P*are the Sample Space, Event and Probability of getting an odd number by throwing the dice, respectively.

S = {1, 2, 3, 4, 5, and 6}

E = {1, 3, 5} *P(E) =**n(E)**n(S)*

(Since, P(E) is the probability of getting an event E, n(E) is the number of elements in the event E and n(S) is the number of elements in the sample space S )

P(E) =3 6

=1 2 - Hence, the probability of getting an odd number is
1 2