Find an equation of the circle with center at origin and radius 444.


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Answer:

x2+y2=16x2+y2=16x2+y2=16

Step by Step Explanation:
  1. The equation of a circle with center at (a,b)(a,b)(a,b) and radius rrr is given by
    (x−a)2+(y−b)2=r2(x−a)2+(y−b)2=r2(x−a)2+(y−b)2=r2
  2. Given:
    Center of the circle is at center i.e(0,0)i.e(0,0)i.e(0,0)
    Radius of the circle =4=4=4
    ⟹a=0,b=0,⟹a=0,b=0,⟹a=0,b=0, and r=4r=4r=4
  3. Therefore, the equation of the circle is given by
    [Math Processing Error]
    Hence, the required equation is x2+y2=16x2+y2=16.

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