### Assume you roll a die 2 times. What is the probability that you will get exactly one 6?

**Answer:**

10 |

36 |

**Step by Step Explanation:**

- According to the question, a die rolled 2 times

So, the Sample Space(**S**) is { (i, j): i, j = 1, 2, 3, 4, 5, 6 } - Total number of outcomes in sample space
**n(S)**= 6 × 6 = 36 - Let
**E**be the event that you will get exactly one 6.

Number of outcomes in which '6' appears only on the first throw = 1 × 5 = 5

As the die is thrown 2 times, '6' (appearing exactly once) can appear on any of the 2 throws.

Therefore, the total number of outcomes when 6 appears exactly once,**n(E)**= 2 × 5 = 10 - Probability, P(E) =

=n(E) n(S) 10 36 - Therefore, the probability of getting exactly one
6

is10 36