### A wireframe is bent into a circle of diameter 56 is reshaped as a rhombus. What is the length of the side of the resulting rhombus? (assume π =

22 |

7 |

**Answer:**

44

**Step by Step Explanation:**

- A wireframe of some length was first bent into a circle and then reshaped as a rhombus:

**Wire****Circle****Rhombus** - Let us first find the length of the wireframe. We know that the total length of the boundary of a circle is called its circumference and is given by:

Circumference = 2πr, where**r**is the radius of the circle.

Since the circle is formed by the wireframe, the length of the wireframe = 2πr

= 2 ×

× 2822 7 **[It is given that the radius of the circle is 56/2 = 28 and π =**

]22 7

= 176 - Now, we know that the same wire frame with length 176 is reshaped as a rhombus. A rhombus has 4 sides and all sides are equal. This means the length of a side of the rhombus will be 176 divided by 4. That is:

176 4

= 44 - Thus the length of the side of the resulting rhombus is
**44**.