A man goes 16 m due west and then 16 m due north. How far is he from the starting point?


Answer:

22.63 m

Step by Step Explanation:
  1. Let us consider a man starting from A and goes from A to B and then from B to C, as shown in the figure.
    Then, AB=16 m,BC=16 m and ABC=90 B A C N W 16 m 16 m
  2. From right ΔABC, we have AC2= AB2+BC2= [(16)2+(16)2] m2= (256+256) m2= 512 m2 Hence, the man is 22.63 \space m away from the starting position.

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