A man goes 16 m due west and then 16 m due north. How far is he from the starting point?
Answer:
22.63 m
- Let us consider a man starting from A and goes from A to B and then from B to C, as shown in the figure.
Then, AB=16 m,BC=16 m and ∠ABC=90∘ - From right ΔABC, we have AC2= AB2+BC2= [(16)2+(16)2] m2= (256+256) m2= 512 m2∴ Hence, the man is 22.63 \space m away from the starting position.