### A die is thrown once. Find the probability of getting a multiple of $3$.

$\dfrac { 1 } { 3 }$

Step by Step Explanation:
1. When a die is thrown, the possible outcomes are $1,2,3,4,5,$ and $6$.

Total number of possible outcomes = $6$.
2. Let $E$ be the event of getting a multiple of $3$.

Then, the favourable outcomes are getting a $3$ and $6$ .

Number of favourable outcomes = $2$. \begin{aligned} \therefore \space P(\text{ getting an a multiple of 3 }) = P(E) = \dfrac { \text { Number of favourable outcomes } } { \text { Total number of outcomes } } = \dfrac { 2 } { 6 } = \dfrac { 1 } { 3 } \end{aligned}